x^2-x+2=0=(x1+1)(x2+1)

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Solution for x^2-x+2=0=(x1+1)(x2+1) equation: 



x^2-x+2=0=(x1+1)(x2+1)

We add all the numbers together, and all the variables

x^2-1x+2=0

a = 1; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·1·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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